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3^(2x)-(2^(2x)+0.5(1-2x))=0
We add all the numbers together, and all the variables
3^2x-(2^2x+0.5(-2x+1))=0
We calculate terms in parentheses: -(2^2x+0.5(-2x+1)), so:We get rid of parentheses
2^2x+0.5(-2x+1)
We multiply parentheses
2^2x-1x+0.5
We add all the numbers together, and all the variables
-1x+2^2x+0.5
Back to the equation:
-(-1x+2^2x+0.5)
3^2x+1x-2^2x-0.5=0
We add all the numbers together, and all the variables
x+3^2x-2^2x-0.5=0
We move all terms containing x to the left, all other terms to the right
x+3^2x-2^2x=0.5
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